Need help to compare two sets of nodes in xsl

Here's peace of my xml: Code:<GetUserMenu>
<MenuList>
<row MenuID="1" MenuTitle="Duomenų pateikimas"/>
</MenuList>
<FunctionList>
<row FunctionID="1" FunctionTitle="Duomenų importavimas iÅ¡ failo" MenuID="1" WorkflowName="ImportDataWithoutF
ile" Order="1"/>
<row FunctionID="2" FunctionTitle="Duomenų įvedimas" MenuID="1" WorkflowName="ImportDataFrom
File" Order="2"/>
</FunctionList>
</GetUserMenu>

and peace of xsl: Code:<xsl:template match="//Authentication/GetUserMenu">
<div>
<xsl:for-each select="//MenuList/row">
<div><xsl:value-of select="@MenuID"/></div>
tu
<xsl:for-each select="//FunctionList/row[">
<div><xsl:value-of select="@MenuID"/></div>
</xsl:for-each>
tu
</xsl:for-each>
</div>
</xsl:template>
I would like to make my xsl do this: 1)In outer for-each cycle xsl reads value of MenuId attribute of of . 2) then in inner cycle for-each my xsl compares that value to every value of MenuAttribute of 's of 3) then my xsl reads the value of MenuId attribute of following of and repeats second step
In normal programming language what i am trying to do would look like this: foreach (xitems as xitem) foreach (yitems as yitem) if xitem == yitem do smth
Could anyone give any advice or modify my code in order to solve my issue? I would be grateful - Full Post